To find the least common multiple (LCM) of two terms, we need to identify the highest power of each unique factor present in both terms. In this case, the LCM of a³b² and a²b⁵ would be a³b⁵, as it includes the highest power of both 'a' and 'b' present in either term. Therefore, the LCM of a³b² and a²b⁵ is a³b⁵.
LCM(a2b5, a3b3) The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
Prime factors of 24 are 23 x 3Prime factors of 36 are 22 x 32The LCM is the product of all the primes to their greatest power,so the LCM of 24aaab and 36abb is 23 x 32 x a3b2 = 72a3b2
The GCF is ab2
ab2
1 over a^5b^3
To find the cross product of two vectors:If a = [a1, a2, a3] and b = [b1, b2, b3], thena x b = [a2b3 - a3b2, a3b1 - a1b3, a1b2 - a2b1] or(a2b3 - a3b2)i + (a3b1 - a1b3)j + (a1b2 - a2b1)k
The LCM is: 210
The LCM for 52, 14, 65 and 91 is 1,820
The LCM of these numbers is 50. LCM is Least Common Multiple.
The LCM is: 10The LCM is 10.
The LCM of these numbers is 340. LCM is Least Common Multiple.
You can't find the LCM of a single number. The LCM of 1, 2, 3 and 14 is 42.