60(:
None. But 4 and 6 have a LCM (not LMC) of 12 and HCF of 2.
The least common multiple (LCM) of 4, 5, and 6 is 60. This is the smallest positive integer that is divisible by all three numbers. To find the LCM, you can list the multiples or use the prime factorization method, which gives you (2^2) (from 4), (5^1) (from 5), and (3^1) (from 6), resulting in (2^2 \times 3^1 \times 5^1 = 60).
30 :D
The LCM is 60.
12
The lowest common multiple is 12
The sample space is the following set: {(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
4* 1 4*2 4*3 4*5 5*1 5*2 5*3 5*4 5*5\ 6*16*2 6*3 6* 4 6*5
The modes are 2, 3, 4, 5 and 6.
1-1 1-2 1-3 1-4 1-5 1-6 2-1 2-2 2-3 2-4 2-5 2-6 3-1 3-2 3-3 3-4 3-5 3-6 4-1 4-2 4-3 4-4 4-5 4-6 5-1 5-2 5-3 5-4 5-4 5-6 6-1 6-2 6-3 6-4 6-5 6-6 So there ARE 36 possible outcomes, you see. Answer BY: Magda Krysnki (grade sevener) :P
In a combination the order does not matter, so they are: 1 1 , 1 2 , 1 3 , 1 4 , 1 5 , 1 6 2 2 , 2 3 , 2 4 , 2 5 , 2 6 3 3 , 3 4 , 3 5 , 3 6 4 4 , 4 5 , 4 6 5 5 , 5 6 6 6
(1, 5, 6, 6), (2, 4, 6, 6), (2, 5, 5, 6), (3, 3, 6, 6), (3, 4, 5, 6), (3, 5, 5, 5), (4, 4, 4, 6), (4, 4, 5, 5).