Use a factor tree. 125 25,5 5,5,5
Since '125' ends in '5' it will divide by '5' , a prime number. Hence 5)125) = 5)25 = 5)5 = 1 When reduced to '1' , the division process is complete. So the factors are '5', '5' & '5'. Hence this would be written explonential form as 5^(3) = 125
The prime factorization of 125 is: 5×5×5
125 25,5 5,5,5
125 is 53 5 is the only prime factor of 125 5x5x5 is the prime factorization
125 = 5 x 5 x 5
5 to the 3rd power, or 5x5x5. so, 5 is a factor of 125
One doesn't have a prime factorization. The prime factorization of 125 is 5 x 5 x 5.
The prime factorization of 125 is: 5 x 5 x 5
125 5 x 25 5 x (5x5) Since 5 is a prime number, the factor tree is complete.
Use a factor tree. 125 25,5 5,5,5
The prime factorization for 125 is:5 X 5 x 5125 is the cube of 55x5x5