No. The square root of 6 is irrational.
The square root of any positive square number is always rational as for example the square root of 36 is 6 which is a rational number.
No because the square root of 36 is 6 which is a rational number
No. A square root of 36 is -6 which, being negative, is not a natural number.The square root of 36 is 6 ... also rational.
The square roots of 36 are Â±6, therefore, sqrt(36) is a rational number.
The square root of 36 is 6 which is a rational number because it can be expressed as an improper fraction in the form of 6/1
No, they are not.
The square root of 39 is not a rational number. It is somewhere between 6 and 7, but can only be written as radical(39). It is a non-ending decimal.No
It is irrational. * The square root of any positive integer, except of a perfect square, is irrational. * The product of an irrational number and a rational number (except zero) is irrational.
The square of 36 is 1,296 ... rational.The square root of 36 is 6 ... also rational.
Yes. It's -6 .
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
For example, in the case of integers: the square root of a positive integer is either an integer (in the case of perfect squares, such as the square root of 1, 4, 9, 16, etc.), or an irrational number (such as the square root of 2, 3, 5, 6, etc.). Similar in the case of the square root of a rational number (fraction): if you don't specifically choose fractions with perfect squares in the numerator and denominator (e.g., 4/9), you will end up with an irrational square root.
No because the square root if 29 is a decimal number. only perfect squares like 36=6 cN be rational or any other squares with a terminating repeating decimal.
The definition of rational means it can be expressed as a fraction were the top and bottom numbers are whole numbers so the negative square root of 36 (-6) is rational because it can be expressed as a fraction -6/1 or 12/-2 or anything like that. Hoped this helped =)
There are an infinite number of rational numbers between these two numbers, but the only positive integer between these numbers is 6.
Every number is a square root of some number. So any number between 5 and 6 is a square root.
6 divided by sqrt(2) is an irrational number and so cannot be represented by a rational fraction.
Yes, because 6 squared = 36 which is a rational number
No. For two reasons: 1) Negative numbers are not natural numbers 2) All natural numbers are rational numbers but the square root of 6 is an irrational number and thus cannot be a natural number.
6 times the square root of 6
Irrational: it amounts to roughly 2.449489743