irrational
No. A square root of 36 is -6 which, being negative, is not a natural number.The square root of 36 is 6 ... also rational.
Every number is a square root of some number. So any number between 5 and 6 is a square root.
4th root of a number is the square root of the square root of the number sqrt (1296) = 36 sqrt (36) = 6 answer: 6
The square root is the number which, multiplied by itself, gives the number you are square rooting.For example,The square root of 36 is 6, because 6 * 6 = 36.* * * * *Note, though, that (-6)*(-6) is also + 36 so -6 is also a square root of 36
No. The square root of 6 is irrational.
The square root of six is irrational. Do you mean a rational approximation?
The square root of any positive square number is always rational as for example the square root of 36 is 6 which is a rational number.
No because the square root of 36 is 6 which is a rational number
The square root of 36 is 6 which is a rational number because it can be expressed as an improper fraction in the form of 6/1
irrational
The square root of 36 is 6 which is a rational number because it can be expressed as an improper fraction in the form of 6/1
The square of 36 is 1,296 ... rational.The square root of 36 is 6 ... also rational.
No. A square root of 36 is -6 which, being negative, is not a natural number.The square root of 36 is 6 ... also rational.
The square roots of 36 are ±6, therefore, sqrt(36) is a rational number.
It is irrational. * The square root of any positive integer, except of a perfect square, is irrational. * The product of an irrational number and a rational number (except zero) is irrational.
The square root of 39 is not a rational number. It is somewhere between 6 and 7, but can only be written as radical(39). It is a non-ending decimal.No