The product of the frequency and wavelength equals the speed of light, c = ƒ• λ
where c is the speed of light in a vacuum, 3.0 x 108m/s, f is the frequency in Hz, and λ is the wavelength in meters.
To solve for wavelength, manipulate the equation so that λ = ƒ/c .
λ = ƒ/c = (4 x 1014Hz)/(3.0 x 108m/s) = 1 x 106m
The wavelength is (speed of the wave) / 2.06 x 1014 .If the wave is an electromagnetic one propagating through vacuum,then the wavelength is3 x 108 / 2.06 x 1014 = 0.001456 millimeter = 1,456 nanometer (rounded)
The higher the frequency, the lower the wavelength. Wavelength
frequency x wavelength = speed of the wave. This applies to all waves, not just to electromagnetic waves.
By frequency on the electromagnetic spectrum
The answer is 5.0*1014 Hertz.
The wavelength is (speed of the wave) / 2.06 x 1014 .If the wave is an electromagnetic one propagating through vacuum,then the wavelength is3 x 108 / 2.06 x 1014 = 0.001456 millimeter = 1,456 nanometer (rounded)
The higher the frequency, the lower the wavelength. Wavelength
frequency x wavelength = speed of the wave. This applies to all waves, not just to electromagnetic waves.
frequency
By frequency on the electromagnetic spectrum
The answer is 5.0*1014 Hertz.
Wavelength = 1/Frequency
Its wavelength/frequency.
frequency
Increasing the frequency of any electromagnetic wave ... or of any wave for that matter ... decreases its wavelength.
Yes. The product of the frequency and the wavelength is the speed of the wave.
For any wave, (wavelength) times (frequency) = (speed of propagation).For electromagnetic waves, (wavelength) times (frequency) = (speed of 'light')