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Q: What is the acceleration between 20 sec and 30 sec?

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Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)

Acceleration = (change in speed) / (change in time) = (30 m/s) / (10 sec) = 3 meters per second2

25 is exactly between 20 and 30.

1 min = 60 sec 30 min = 1800 sec

Probably 'between 20 and 30.'

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Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)

-4 mph/sec (Study Island Answer)

To find the time it takes for the car to travel 30m, we can use the kinematic equation ( s = \frac{1}{2} a t^2), where (s) is distance, (a) is acceleration, and (t) is time. Plugging in the values we have, we get (30 = \frac{1}{2} \times 2 \times t^2). Solving for (t), we find (t = \sqrt{30/1}) = (\sqrt{30}) seconds.

Acceleration = (change in speed) / (change in time) = (30 m/s) / (10 sec) = 3 meters per second2

South Carolina 20 LSU 20 September 30, 1995

25 is exactly between 20 and 30.

1 min = 60 sec 30 min = 1800 sec

Acceleration = (force)/(mass)For the first object, A = 20/10 = 2 m/s2For the second object, A = 30/18 = 12/3 m/s2The acceleration of the first object is 20% greaterthan the acceleration of the second one.

25 is a perfect square occurring between 20 and 30.

Probably 'between 20 and 30.'

Speed is the rate at which an object moves, while acceleration is the rate at which the speed of an object changes. Speed is a scalar quantity (has magnitude only), while acceleration is a vector quantity (has magnitude and direction).

20 is between 10 and 30.