Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
Acceleration = (change in speed) / (change in time) = (30 m/s) / (10 sec) = 3 meters per second2
25 is exactly between 20 and 30.
1 min = 60 sec 30 min = 1800 sec
Probably 'between 20 and 30.'
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 20+10 = 30 miles/sec, the initial velocity is 20 miles/sec, and the time is 30 seconds. So, the acceleration of the car is (30 - 20) / 30 = 0.33 miles/sec^2.
Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
-4 mph/sec (Study Island Answer)
The car's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: (30 m/s - 20 m/s) / 10 sec = 1 m/s^2. The car's acceleration is 1 meter per second squared.
To find the time it takes for the car to travel 30m, we can use the kinematic equation ( s = \frac{1}{2} a t^2), where (s) is distance, (a) is acceleration, and (t) is time. Plugging in the values we have, we get (30 = \frac{1}{2} \times 2 \times t^2). Solving for (t), we find (t = \sqrt{30/1}) = (\sqrt{30}) seconds.
Acceleration = (change in speed) / (change in time) = (30 m/s) / (10 sec) = 3 meters per second2
South Carolina 20 LSU 20 September 30, 1995
25 is exactly between 20 and 30.
1 min = 60 sec 30 min = 1800 sec
Probably 'between 20 and 30.'
25 is a perfect square occurring between 20 and 30.
Acceleration = (force)/(mass)For the first object, A = 20/10 = 2 m/s2For the second object, A = 30/18 = 12/3 m/s2The acceleration of the first object is 20% greaterthan the acceleration of the second one.