Well, isn't that just a happy little question! To find the acceleration between 20 seconds and 30 seconds, you would need to calculate the change in velocity during that time interval and divide it by the time taken. Remember, acceleration is how quickly an object's velocity is changing over time. Just like adding a touch of bright color to a painting, understanding acceleration can add a beautiful depth to your knowledge of motion.
Oh, dude, acceleration is just the rate of change of velocity over time, so you'd just calculate the difference in velocity at 20 seconds and 30 seconds, then divide by the time interval. It's like the speedometer in your car, but fancier. So, the acceleration between 20 sec and 30 sec is just the change in velocity divided by 10 seconds. Easy peasy!
Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
Acceleration = (change in speed) / (change in time) = (30 m/s) / (10 sec) = 3 meters per second2
25 is exactly between 20 and 30.
1 min = 60 sec 30 min = 1800 sec
Probably 'between 20 and 30.'
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 20+10 = 30 miles/sec, the initial velocity is 20 miles/sec, and the time is 30 seconds. So, the acceleration of the car is (30 - 20) / 30 = 0.33 miles/sec^2.
Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
The car's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: (30 m/s - 20 m/s) / 10 sec = 1 m/s^2. The car's acceleration is 1 meter per second squared.
-4 mph/sec (Study Island Answer)
To find the time it takes for the car to travel 30m, we can use the kinematic equation ( s = \frac{1}{2} a t^2), where (s) is distance, (a) is acceleration, and (t) is time. Plugging in the values we have, we get (30 = \frac{1}{2} \times 2 \times t^2). Solving for (t), we find (t = \sqrt{30/1}) = (\sqrt{30}) seconds.
Acceleration = (change in speed) / (change in time) = (30 m/s) / (10 sec) = 3 meters per second2
South Carolina 20 LSU 20 September 30, 1995
25 is exactly between 20 and 30.
1 min = 60 sec 30 min = 1800 sec
Acceleration = (force)/(mass)For the first object, A = 20/10 = 2 m/s2For the second object, A = 30/18 = 12/3 m/s2The acceleration of the first object is 20% greaterthan the acceleration of the second one.
Probably 'between 20 and 30.'
25 is a perfect square occurring between 20 and 30.