yes
They are are 62, 63 and 64.
The number can be 38 (38/3=12R2), 50 (50/4=12R2), 62 (62/5=12R2) and so on.
1 + 2 + 3 + 5 + 6 + 10 + 15 + 30 = 62.
a + a+3 = 65 2a = 62 a=31 so the other must be 34
6 6+(3*62) = 114
If the four friends were born in consecutive years, we can represent their ages as (x), (x+1), (x+2), and (x+3). The sum of their ages is given by the equation (x + (x+1) + (x+2) + (x+3) = 62), which simplifies to (4x + 6 = 62). Solving for (x), we find (4x = 56) or (x = 14). Thus, the ages of the friends are 14, 15, 16, and 17, making the oldest friend 17 years old.
Ages 1, 4 and 6
9 and 6 9-6 = 3 92+62 = 117
William Morris died on October 3, 1896 at the age of 62.
David Hemmings died on December 3, 2003 at the age of 62.
Joseph Quesnel died on July 3, 1809 at the age of 62.
Robert Noyce died on June 3, 1990 at the age of 62.