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First of all I woulod switch it around so it would be 36-4+k. Since the negative sign is the same as subtracting. So the final answers going to be 32+k.
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∙ 13y ago
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What is k plus 1 plus k plus 4?
2k + 5
2x plus 36 4?
The value of X in the equation 2x plus 36 = 4 is -16.
What is 1 plus 4 plus 16 plus 25 plus 36 plus 49?
1 + 4 + 16 + 25 + 36 + 49 = 131
What is 36 divided by 4 plus 22?
36 divided by 4 is 9 and 9 plus 22 equels 31
What is the value of k when the straight line of y equals 3x plus 1 touches the curve of x squared plus y squared equals k at one point showing work with answer?
If: x^2+y^2 = k and y = 3x+1 Then: x^2+(3x+1)^2 = k => x^2+9x^2+6x+1 = k Collecting like terms and subtracting k from both sides: 10x^2+6x+(1-k) = 0 For the line to touch the curve at one point the discriminant of b^2-4(ac) must = 0 So: 36-4*10*(1-k) = 0 => 36-40+40k = 0 => 40k = 40-36 => 40k = 4 Therefore: k = 4/40 and in its lowest terms 1/10
How would you work out the possible values of k in the line y equals kx plus 1 which is tangent to the curve of y equals 3x squared -4x plus 4?
If: y = kx+1 and y = 3x2-4x+4 Then: 3x2-4x+4 = kx+1 So: 3x2-4x-kx+3 = 0 For the line to be tangent to the curve the discriminant of b2-4ac must = 0 So when: -4*3*3 = -36 then (-4-k)2 must = 36 So it follows: (-4-k)(-4-k) = 36 => k2+8k-20 = 0 Solving the quadratic equation: k = 2 or k = -10
What is K 9?
is multiplication , so you multiply like k(9)=36 then k would equal k=4 because you divide 9 by 36 and it equals =4
What is k plus 1 plus k plus 4?
2k + 5
2x plus 36 4?
The value of X in the equation 2x plus 36 = 4 is -16.
What is 1 plus 4 plus 16 plus 25 plus 36 plus 49?
1 + 4 + 16 + 25 + 36 + 49 = 131
What is 36 divided by 4 plus 22?
36 divided by 4 is 9 and 9 plus 22 equels 31
What is the square root of 36 plus 4?
sqrt(36) + 4 = 6 + 4 = 10
What is the answer for 9 plus 4?
36
What is the value of k when the straight line of y equals 3x plus 1 touches the curve of x squared plus y squared equals k at one point showing work with answer?
If: x^2+y^2 = k and y = 3x+1 Then: x^2+(3x+1)^2 = k => x^2+9x^2+6x+1 = k Collecting like terms and subtracting k from both sides: 10x^2+6x+(1-k) = 0 For the line to touch the curve at one point the discriminant of b^2-4(ac) must = 0 So: 36-4*10*(1-k) = 0 => 36-40+40k = 0 => 40k = 40-36 => 40k = 4 Therefore: k = 4/40 and in its lowest terms 1/10
What are multiples of 4 and 9?
They are members of the infinite set of numbers of the form 36*k where k is an integer.
What is 32 plus 4?
32 + 4 = 36
What is X if -8x plus 4 equals 36?
If: -8x+4 = 36 then the value of x works out as -4 Check: -8*(-4)+4 = 36
