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If: y = kx+1 and y = 3x2-4x+4

Then: 3x2-4x+4 = kx+1

So: 3x2-4x-kx+3 = 0

For the line to be tangent to the curve the discriminant of b2-4ac must = 0

So when: -4*3*3 = -36 then (-4-k)2 must = 36

So it follows: (-4-k)(-4-k) = 36 => k2+8k-20 = 0

Solving the quadratic equation: k = 2 or k = -10

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Q: How would you work out the possible values of k in the line y equals kx plus 1 which is tangent to the curve of y equals 3x squared -4x plus 4?
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