4*4*4 + 44*44 = 2000.
£2000
There are 7 significant figures in this number.
To get six 4s to make the sum of 10, you can use the following mathematical expression: (4/4) + (4/4) + (4+4) = 10. In this equation, you are dividing 4 by 4 to get 1, then adding that to another 1 from the second set of divided 4s, and finally adding the sum of the remaining two 4s to get 10.
The difference between the number of 2s and the number of 4s in a sum.
You can get 9 with the sum 4 + 4 + (4/4) = 9
Answer is 4000000: The sum of the first N odd numbers is N^2. Look at 1,3,5 for example. There are 3 numbers and the sum is 9 which is 3^2. Add 7 and the sum is 16 which is 4^2. So the of the first 2000 consecutive odd numbers is 2000^2 Note 2000 is 2(10^3). When we square that it is 4x10^6=4000000
4s^2 + s - 14 = (4s - 7)(s + 2)
s=-7/4
20
yes 2000
x-7
The sum of 11 and 7 is 18.