a = [1] Simple as that!!
did you mean an identity matrix (I)?
then a would equal:
a= [ 1 0 0
0 1 0
0 0 1 ]
All 1's down the main diagonal
Let me know what the size of the matrix is and put brackets around the rows so I can understand the question. I can help with linear algebra
For example, if you have [ -4 1 0 3] as your matrix, it would be negative 4. Whatever negative number is in your matrix is your answer.
idiosyncrasies of matrix are the differences between matrix algebra and scalar one. i'll give a few examples. 1- in algebra AB=BA which sometimes doesn't hold in calculation of matrix. 2- if AB=0, scalar algebra says, either A, B or both A and B are equal to zero. this also doesn't hold in matrix algebra sometimes. 3- CD=CE taking that c isn't equal to 0, then D and # must be equal in scalar algebra. Matrix again tend to deviate from this identity. its to be noted that these deviations from scalar algebra arise due to calculations involving singular matrices.
Let A by an nxn non-singular matrix, then A-1 is the inverse of A. Now (A-1 )-1 =A So the answer is yes.
It isn't; the algebra 1 and 2 that you get taught in middle or high school is elementary algebra. When (if you want to) you get into more advanced algebra, you can learn linear algebra (matrix algebra) and abstract algebra (which involves sets, operations on sets, groups, and many more concepts), and probably several more types of algebra I've never heard of.
8n = 1 n = 1/8
1=6x x=1/6
1/a = 1/b: cross multiplying gives a = b
Yes. Matrix addition is commutative.
I think there's a typo, otherwise -3 = 1
A = coefficient matrix (n x n) B = constant matrix (n x 1)
It is missing some information so, is therefore is an incomplete output.