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d = 9
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-d plus 2 equals 5?
-d + 2 = 5(- 2 from both sides)-d = 3(x both sides by -1)d = -3
What does d mean in 1 x c x 3 equals d?
d=3c
1 plus x equals b c plus x equals d d plus x equals 89 b plus x equals c d equals?
1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)
What is the volume of a cylinder with the height of 14 feet and a diameter of 18 feet?
V = pi x D^2 /4 x height = 3.14 x 18 x 18 x 14 /4 = 3561 cu ft
What is the antiderivative of e to the power of one divided by -x?
Powers of e are simple to integrate. The derivative of eu equals u'eu; inversely, the antiderivative of eu equals eu/u'. Therefore, the antiderivative of e1/-x equals (e1/-x)/{d/dx[1/-x]}. The derivative of 1/-x, which can also be expressed as x-1, equals (-1)x(-1-1) = -x-2 = -1/x2.
-d plus 2 equals 5?
-d + 2 = 5(- 2 from both sides)-d = 3(x both sides by -1)d = -3
What is 4 over x equals 5 over x minus 1 over 2 These are fractions NOT division problems?
x = 2 :D
What is circumference of the circle d equals 6ft?
Circumference = r x pi and d = 2r. So, r = d/2 = 6/2 = 3ft and Circumference = 3ft x 3.14 = 9.42.
What does d mean in 1 x c x 3 equals d?
d=3c
What is AB equals C plus D?
AB = 2 x 4 (8) C = 3 D = 5
1 plus x equals b c plus x equals d d plus x equals 89 b plus x equals c d equals?
1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)
What is the derivative of y equals sin times x to the power of 2?
D(y)= sin 2x
Given that ABCD is a rhombus find the value of x when a equals x and d equals x plus 14?
29
What is the volume of a cylinder with the height of 14 feet and a diameter of 18 feet?
V = pi x D^2 /4 x height = 3.14 x 18 x 18 x 14 /4 = 3561 cu ft
What is the distance between z-intercept from x-intercept in the equation ax plus by plus cz equals d?
-- At the z-intercept, x=0, y=0, cz=d, so z=d/c.-- At the x-intercept, y=0, z=0, ax=d, so x=d/a.The distance between the two points is sqrt[ (d/c)2 + (d/a)2 ] or d sqrt[ (1/c)2 + (1/a)2 ].
How do you find the equation of a line tanget to y equals x raised to the 2nd power minus 2sinx plus 3 at 0 comma 3?
Take the derivative of the equation with respect to x: dy/dx = d(x^2-2sin(x)+3)/dx =d(x^2)/dx-2*d(sin(x))/dx+d(3)/dx =2x-2*cos(x) That's your tangent equation. At x=0 ---> 2*0-2*cos(0) = -2 There's your slope.
What is the gradient of the tangent to the curve at x equals 2 if Y equals x2?
Gradient to the curve at any point is the derivative of y = x2 So the gradient is d/dx of x2 = 2x. When x = 2, 2x = 4 so the gradient of the tangent at x = 2 is 4.
