-d + 2 = 5(- 2 from both sides)-d = 3(x both sides by -1)d = -3
d=3c
V = pi x D^2 /4 x height = 3.14 x 18 x 18 x 14 /4 = 3561 cu ft
1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)
Powers of e are simple to integrate. The derivative of eu equals u'eu; inversely, the antiderivative of eu equals eu/u'. Therefore, the antiderivative of e1/-x equals (e1/-x)/{d/dx[1/-x]}. The derivative of 1/-x, which can also be expressed as x-1, equals (-1)x(-1-1) = -x-2 = -1/x2.
-d + 2 = 5(- 2 from both sides)-d = 3(x both sides by -1)d = -3
x = 2 :D
Circumference = r x pi and d = 2r. So, r = d/2 = 6/2 = 3ft and Circumference = 3ft x 3.14 = 9.42.
AB = 2 x 4 (8) C = 3 D = 5
d=3c
V = pi x D^2 /4 x height = 3.14 x 18 x 18 x 14 /4 = 3561 cu ft
D(y)= sin 2x
1+x=dd+x so dd=1 so d=1 1+x=89b+x so 89b=1 so b=1/89 bc+x=1+x so bc=1 so c=1/(1/89) = 89 so cd=89 (and x=88)
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-- At the z-intercept, x=0, y=0, cz=d, so z=d/c.-- At the x-intercept, y=0, z=0, ax=d, so x=d/a.The distance between the two points is sqrt[ (d/c)2 + (d/a)2 ] or d sqrt[ (1/c)2 + (1/a)2 ].
Take the derivative of the equation with respect to x: dy/dx = d(x^2-2sin(x)+3)/dx =d(x^2)/dx-2*d(sin(x))/dx+d(3)/dx =2x-2*cos(x) That's your tangent equation. At x=0 ---> 2*0-2*cos(0) = -2 There's your slope.
Gradient to the curve at any point is the derivative of y = x2 So the gradient is d/dx of x2 = 2x. When x = 2, 2x = 4 so the gradient of the tangent at x = 2 is 4.