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It could be many things. If x and y are different non-zero positive integers, then x=1 and y=4. (if x is zero, Y is 6 ; if y is zero, x is 3)
Otherwise, any answer would be correct where x = (6-y)/2 or y=6-2x.
For two unknowns, x and y, you need two independent equations to get numerical solutions.
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Which line is parallel to y equals -2x plus 6?
[ y = -2x + any other number ] is parallel to [ y = -2x + 6 ].
Y equals 2x plus 6 what is the y intercept?
x=0 y=6
2x plus y equals 8 and x plus y equals 6?
x = 2y = 4
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
What are the order pairs for x equals y plus 3 and 2x plus y equals -3?
The answer is - not are - (-6, 9).
Is y equals 2x-6 and y equals one half plus 3 perpendicular to each other?
No but y = -1/2x+3 is perpendicular to y = 2x+6
Which line is parallel to y equals -2x plus 6?
[ y = -2x + any other number ] is parallel to [ y = -2x + 6 ].
What is the solution of the system Use substitution. y equals x plus 6 y equals 2x?
If: y = x+6 and y = 2x Then: x+6 = 2x And: 6 = 2x-x => 6 = x So: x = 6 and y = 12
If 2x plus 1 equals y what does 12x plus 6 equals?
6y
2x plus y equals -6 3x plus y equals -10?
x = -4 and y = 2
Y equals 2x plus 6 what is the y intercept?
x=0 y=6
2x plus y equals 8 and x plus y equals 6?
x = 2y = 4
What type of lines are these y equals 2x plus 4 and 12 equals 2y plus x?
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
What are the order pairs for x equals y plus 3 and 2x plus y equals -3?
The answer is - not are - (-6, 9).
3x - y equals 3 y equals 2x plus 2?
3x-y = 3y3x = 4yy = 0.75x3x-0.75x = 2x+22.25x = 2x+20.25x = 2x = 8y = 6
What is the answer to Y equals 2X plus 6 2X-Y equals 2?
eqn 1 Y = 2X + 6 eqn 2 2X - Y = 2 Rearrange eqn2 to isolate Y eqn2 Y = 2X - 2 so 2X + 6 = 2X - 2 subtracting 2X from both sides we get 6 = -2 As this is impossible this set of equations can not be solved.
