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Why is it easier to count by 5s or 10s and 2s instead of counting by 3s or 4s?
It is only because we count in tens - and 5 10 and 2 are factors.
What is the sum of one-half of s one-fifth of x and 7?
(1/2s)+(1/5x)+7 5s+2x+7 5s=2x+7 s=2/5x+7/5 (1/2(2/5x+7/5))+(1/5x)+7 1/5x+3.5/5+1/5x+7 2/5x+7 7/10 2/5x=-7 7/10 x=-19.25 (1/2s)+(1/5x)+7 1/2s-3.85+7 1/2s+3.15 1/2s=-3.15 s=-6.3 (1/2s)+(1/5x)+7 1/2(-6.3)+1/5(-19.25)+7 -3.15-3.85+7 0 In the end, it equals 0 because there were no values for x and s and since I started with just an equation with nothing on the other side, I used (by default) 0 on the other side.
How can you make 2s equal 5?
If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
-v plus 5 plus 6v equals 1 plus 5v plus 3?
-v + 5 + 6v = 1 + 5v + 3Clean up and combine each side:(-v + 6v) + 5 = (1 + 3) + 5v5v + 5 = 4 + 5vSubtract 5v from each side:5 = 4.There is no solution.No value of 'v' can make [ 5 = 4 ].
How do you factor -20v plus 4v2 - 5y plus vy?
-20v + 4v2 - 5y + vy = 4v2 - 20v + vy - 5y = 4v*(v - 5) + y*(v - 5) = (4v + y)*(v - 5)
Use substitution to prove that 2s + 3squared is not equivalent to 5s?
if s is 2, 2s is 4. 3 squared is 9. 4 + 9 = 13. 13 / 5 = 2.6, which is not equal to 2.
Why is it easier to count by 5s or 10s and 2s instead of counting by 3s or 4s?
It is only because we count in tens - and 5 10 and 2 are factors.
What is s and t when 2s add 3t is 28 and 5s add 6t is 61?
That's a simple example of system of equations. There are quite a number of methods for solving those, but the easiest here would be to calculate one variable from first equation and substitute it into second. 2s + 3t = 28 5s + 6t = 61 Let's calculate s from the first equation: 2s + 3t = 28, 2s = 28 - 3t s = 14 - 3t/2 Substitute s into second equation 5s + 6t = 61, 5(14 - 3t/2) + 6t = 61, 70 - 15t/2 + 6t = 61, 70 - 3t/2 = 61, 3t/2 = 9, t = 6. We can then substitute t back into first equation: 2s + 3t = 28, 2s + 3 * 6 = 28, 2s = 10, s = 5. So the final answer is: s = 5 t = 6
How do you factor 180v2-245?
5(6v + 7)(6v - 7)
Which is better the iPhone 5 or the iPhone 5s?
5s
If p equals 2s plus 5 what is s in terms of p?
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
What is the sum of one-half of s one-fifth of x and 7?
(1/2s)+(1/5x)+7 5s+2x+7 5s=2x+7 s=2/5x+7/5 (1/2(2/5x+7/5))+(1/5x)+7 1/5x+3.5/5+1/5x+7 2/5x+7 7/10 2/5x=-7 7/10 x=-19.25 (1/2s)+(1/5x)+7 1/2s-3.85+7 1/2s+3.15 1/2s=-3.15 s=-6.3 (1/2s)+(1/5x)+7 1/2(-6.3)+1/5(-19.25)+7 -3.15-3.85+7 0 In the end, it equals 0 because there were no values for x and s and since I started with just an equation with nothing on the other side, I used (by default) 0 on the other side.
What is the answer to this algebra question 4v - 7 plus 8v plus 4 - 5?
Is it 4v-7+8v+4-5 ? If so then you're answer is 12v-8
How do 5 5s make 24?
5/5=1 Keep this for later. so 2 5s used. Then do 5*5=25, so 5 5s used as 25 has a five in it, now do 1 - 25=24.
How can you make 2s equal 5?
If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
What is 5s-3 when s equals 5?
22 5s - 3 = 5(5) - 3 = 25-3 = 22
Is the iPhone 5S an upgraded iPhone 5?
It is correct to say iPhone 5S is an upgraded iPhone 5.
