Wiki answer limits your ability to insert operators in questions, so please write out the word "equals" or "plus" as it is necessary.
If the question is 3(x-1) = 15, you divide 15 by 3. That tells you what x-1 is. Then you add 1. That's x.
x = 1/3
4
x2-2x-3 = 0 (x+1)(x-3) = 0 x = -1 or x = 3
2x2-x-3 = 0= 4 - x - 3 = 0= 1 - x = 0= 1 = xTherefore x = 1
If that's + 2x2, the answer is x(x + 3)(x - 1) x = 0, -3, 1 If that's - 2x2, the answer is x(x - 3)(x + 1) x = 0, 3, -1
how do you solve 14+x-11-x+x-3=1
1-3x1=3x 1/3=x
5X-3 - X-1 + X + 6 The answerdepends on value of X
If we assume that it equals zero and you wish to solve for x, then the answer is:-x2 + 2x - 3 = 0x2 - 2x + 3 = 0x2 -2x + 1 = -2(x - 1)2 = -2x - 1 = ± √(-2)x = 1 ± i√2
9/1 x 1/3 = 9/3 = 3
1