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-1/72x4 + c where c is the constant of integration.

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โˆ™ 2010-09-29 09:44:21
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Q: What is the antiderivative of 1 divided by 18x5?
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What is the antiderivative of x to the -1?

Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C

What is the antiderivative of e to the power of one divided by -x?

Powers of e are simple to integrate. The derivative of eu equals u'eu; inversely, the antiderivative of eu equals eu/u'. Therefore, the antiderivative of e1/-x equals (e1/-x)/{d/dx[1/-x]}. The derivative of 1/-x, which can also be expressed as x-1, equals (-1)x(-1-1) = -x-2 = -1/x2.

What is the antiderivative of x to the 1?

By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2

What is the integral of x divided by x plus 1?

x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,

What is the answer of 18x5?


Is there any other anti derivative of 1 divided by x?

The antiderivative of 1/x is ln(x) + C. That is, to the natural (base-e) logarithm, you can add any constant, and still have an antiderivative. For example, ln(x) + 5. These are the only antiderivatives; there are no different functions that have the same derivatives. This is valid, in general, for all antiderivatives: if you have one antiderivative of a function, all other antiderivatives are obtained by adding a constant.

What is the anti derivative of the square root of 1-x2?


What is the antiderivative of 2x?

The antiderivative of 2x is x2.

What is the antiderivative of logx?

X(logX-1) + C

What is the antiderivative of 1 over xlnx?

It is ln(ln(x))

How do you solve g x equals -3x plus 1?

If: x = -3x+1 Then: x+3x = 1 => 4x =1 So: x = 1/4 or 0.25 ----------- I notice that the question requests a solution for g x = -3x + 1. It seems possible that parentheses around the 'x' after the 'g' have gone missing, along with a prime indicating the derivative of the function g. This being the case, we would be seeking the antiderivative of -3x + 1. The antiderivative of a sum is the sum of the antiderivatives. So we can look at -3x and +1 separately. The derivative of x2 is 2x. Therefore, the antiderivative of x is x2/2, and the antiderivative of -3x is -3x2/2. The antiderivative of 1 is x. Overall, the solution is the antiderivative -3x2/2 + x + C, where C is an arbitrary constant.

What is the antiderivative of x to the negative 6 5ths?

(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)

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