If: x = -3x+1
Then: x+3x = 1 => 4x =1
So: x = 1/4 or 0.25
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I notice that the question requests a solution for g x = -3x + 1.
It seems possible that parentheses around the 'x' after the 'g' have gone missing, along with a prime indicating the derivative of the function g. This being the case, we would be seeking the antiderivative of -3x + 1.
The antiderivative of a sum is the sum of the antiderivatives. So we can look at -3x and +1 separately.
The derivative of x2 is 2x. Therefore, the antiderivative of x is x2/2, and the antiderivative of -3x is -3x2/2.
The antiderivative of 1 is x.
Overall, the solution is the antiderivative -3x2/2 + x + C, where C is an arbitrary constant.
x = 5, y = -1
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
Simple algebra. 1 + 3x = -x - 4 3x = -x - 5 -3x = x + 5 -4x = 5 x = -1.25
you mean: y= -3x+1 y+x=-3+1 solve -3+1= -2 y+x = -2
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
x = 5, y = -1
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
Simple algebra. 1 + 3x = -x - 4 3x = -x - 5 -3x = x + 5 -4x = 5 x = -1.25
you mean: y= -3x+1 y+x=-3+1 solve -3+1= -2 y+x = -2
(3x + 1) = -3 (x + 2x -1) (3x + 1) = -3 (3x - 1) 3x + 1 = -9x + 3 12x = 2 6x = 1 x = 0.16666666666666666666666666666666666666666666666666666666666666666666
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
(2, -1)
3x2 + x - 2 = 0(3x - 2) (x + 1) = 0x = + 2/3x = -1
3x+5=4-2x+6 5x=4-1 5x=3 x=3/5
y = 3X - 1
y = 3x + 1