If: x = -3x+1
Then: x+3x = 1 => 4x =1
So: x = 1/4 or 0.25
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I notice that the question requests a solution for g x = -3x + 1.
It seems possible that parentheses around the 'x' after the 'g' have gone missing, along with a prime indicating the derivative of the function g. This being the case, we would be seeking the antiderivative of -3x + 1.
The antiderivative of a sum is the sum of the antiderivatives. So we can look at -3x and +1 separately.
The derivative of x2 is 2x. Therefore, the antiderivative of x is x2/2, and the antiderivative of -3x is -3x2/2.
The antiderivative of 1 is x.
Overall, the solution is the antiderivative -3x2/2 + x + C, where C is an arbitrary constant.
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x = 5, y = -1
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
Simple algebra. 1 + 3x = -x - 4 3x = -x - 5 -3x = x + 5 -4x = 5 x = -1.25
you mean: y= -3x+1 y+x=-3+1 solve -3+1= -2 y+x = -2
(2, -1)