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Split it into 7 triangles. Half-base of each is 2 so distance of centre to mid point of base is (Pythagoras) square root of (4.62 - 22) = 4.162 So area of each triangle is this times 2, and with 7 triangles multiply also by 7 to get an approximate area of 58 sq in.

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Q: What is the approximate area of a regular heptagon with a side length of 4 inches and a distance from the center to a vertex of 4.6 inches?
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