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What is the approximate energy of a photon having a frequency of 4 100000000 Hz?
Wiki User
∙ 13y ago
E=h*f
h is Planck's constant, which is equal to 6.62 x 10-34 J . s.
f is the frequency in Hz.
Multiplication of two numbers together is left as an exercise to the student.
3.2 x 10-18 J
acutual answer on The Question is 4.3 x 10-19J
Wiki User
∙ 14y ago
Wiki User
∙ 9y agoThe energy of a photon of frequency 1.25 x 10^6 Hz can be calculated using the relation E = hf, where E is the energy in Joules, h is Planck's constant 6.63 x 10^-34 m^2 kg / s, and f is the frequency in cycles per second (Hz). The energy of this photon is 8.28 x 10^-28 J.
Wiki User
∙ 13y agoTo calculate this we use the de Broglie equation f=E/h, where f is the frequency, E is the energy of the particle and h is Planck's constant.
The energy of a photon with a frequency of 4100000000 Hz then equals:
E= f*h = 4100000000 Hz * 6.626068 * 10^-34 Js = 2.71*10^-24 J
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