What is the area for 19 16 24 in?

Answer 1

Assuming the shape is a triangle, the area is 151.65 sq in.

A = √[s(s - a)(s - b)(s - c)], where s = the semi-perimeter, a, b, and c are the side lengths.

Let a = 19, b = 16, c = 24, and s = (19 + 16 + 24)/2 = 29.5

So we have,

A = √[s(s - a)(s - b)(s - c)] = √[29.5(29.5 - 19)(29.5 - 16)(29.5 - 24)] = 151.65 in2.