3492 in2
An area cannot be 36 inches. However, assuming that the area was meant to be 36 SQUARE inches, then pi*r2 = 36 so r = sqrt(36/pi) = 3.39 inches.
if 36 is the area it already is square inches.
36 square inches is the area.
The area of a square whose perimeter is 36 inches is: 81 square inches.
There are 12 inches in a foot so the area becomes 48 by 36 inches. Total area is 48 x 36 = 1728 square inches
The area of the square will be: 36 times 36 = 1296 square inches
To find the area of a square, you multiply the length of one side by itself. In this case, if the sides are 6 inches long, the area would be 6 inches * 6 inches = 36 square inches.
You cannot. First of all, an area cannot be 6 inches since that is a measure of distance, not of an area. So a rectangle with an area of 36 inches is impossible. In any case, assuming the area is 36 SQUARE inches and that the length of the rectangle is at least as great as the width, all that you can say is that the width is at most 6 inches. Suppose the length is L inches where L >= 6 inches. and let W = 36/L inches. Then Area = L*W = L*36/L = 36 sq inches as required. But W is indeterminate.
The area is 324*n*cotangent(180/n) where n is the number of sides in the polygon.
81 square inches
12 inches.
The dimensions of a square with an area 36 square inches are:Side lengths: Six inchesPerimeter: 24 inchesDiagonal measurement: 8.485 inches