10x130=1300
x = width length = x + 3 (3+x)(x) = area (4+x)(x) = area +10 let area = y 3x + x^2 = y 4x+x^2 = y +10 substitute 4x + x^2 = 3x+x^2 + 10 x =10 = width length = 13
You need to find the area which is length x width. For the first area: 10 x 3.5 =35 square feet. For the second area: 13 x 4=52 square feet.
13 - 10% = 13 x (1 - (10/100)) = 13 x 0.9 = 11.7
You can't tell. The perimeter doesn't tell you the area. There are an infinite number of rectangles that all have the same perimeter but different areas. Here are a few that all have perimeters of 28 cm: 1 x 13 . . . . . Area = 13 2 x 12 . . . . . Area = 24 3 x 11 . . . . . Area = 33 4 x 10 . . . . . Area = 40 5 x 9 . . . . . Area = 45 6 x 8 . . . . . Area = 48 7 x 7 . . . . . Area = 49
If: -3-x = 10 Then: x = -13
(9/13) / (10/13) =(9/13) x (13/10) =9/10
If: -3-x = 10 Then: x = -13
x + 3 + 10 = x + 13
The equation:3 x 2 + 5 x 2 - 13 - 10 / 2= (3 x 2) + (5 x 2) - 13 - (10 / 2)= 6 + 10 - 13 - 5= -2
To calculate the area of a room, you multiply its length by its width. For a room that measures 13 feet by 10 feet, the area is 13 x 10 = 130 square feet. Therefore, the room has an area of 130 square feet.
To find the area of the metal frame, we first calculate the area of the circle and the area of the square. The radius of the mirror is (5x), so the area of the circle is (\pi (5x)^2 = 25\pi x^2). The side length of the square is (15x), so the area of the square is ((15x)^2 = 225x^2). The area of the metal frame is the area of the square minus the area of the circle: [ 225x^2 - 25\pi x^2 = (225 - 25\pi)x^2. ] Thus, the area of the metal frame in factored form is ((225 - 25\pi)x^2).
17 x 13 = 221 221/23.97 = 9.22 9.22 boxes or 10 whole boxes.