10x130=1300
x = width length = x + 3 (3+x)(x) = area (4+x)(x) = area +10 let area = y 3x + x^2 = y 4x+x^2 = y +10 substitute 4x + x^2 = 3x+x^2 + 10 x =10 = width length = 13
You need to find the area which is length x width. For the first area: 10 x 3.5 =35 square feet. For the second area: 13 x 4=52 square feet.
13 - 10% = 13 x (1 - (10/100)) = 13 x 0.9 = 11.7
You can't tell. The perimeter doesn't tell you the area. There are an infinite number of rectangles that all have the same perimeter but different areas. Here are a few that all have perimeters of 28 cm: 1 x 13 . . . . . Area = 13 2 x 12 . . . . . Area = 24 3 x 11 . . . . . Area = 33 4 x 10 . . . . . Area = 40 5 x 9 . . . . . Area = 45 6 x 8 . . . . . Area = 48 7 x 7 . . . . . Area = 49
If: -3-x = 10 Then: x = -13
(9/13) / (10/13) =(9/13) x (13/10) =9/10
If: -3-x = 10 Then: x = -13
x + 3 + 10 = x + 13
The equation:3 x 2 + 5 x 2 - 13 - 10 / 2= (3 x 2) + (5 x 2) - 13 - (10 / 2)= 6 + 10 - 13 - 5= -2
What is the area of a rectangle 5.8 x 10??
17 x 13 = 221 221/23.97 = 9.22 9.22 boxes or 10 whole boxes.
13 > -10 + x/4 if 23 > x/4 if 92 > x that is, when x < 92