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The area of a hexagon with an inradius (apothem) of 0.88m is 2.683m2

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  • If the inradius is the distance from the hexagon center to any of the hexagon vertices and that the hexagon is composed of six triangles.
  • then, the area of the hexagon = 6x1/2xinradius2 x 31/2 /2
= 3 x 3 1/2 x inradius2/2= 6 x 0.5 x 0.7744 x 1.73205/2= 2.0119502 sq meter
  • However, if the inradius is the distance between the hexagon center and the midpoint of a side (apothem) and that the hexagon is composed of six triangles
  • then, the area = 6 x inradius 2 / 31/2
= 6 x 0.88 2 / 1.73205 sq meter = 2.6826015 sq meter
  • Refer to link below
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Q: What is the area of a hexagon with an inradius of 0.88m?
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