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Which is the area of a parallelogram with a base of 8 centimeters and a height of 14 centimeters?
Area = Base * vertical height = 8*14 = 112 cm2
What is the area of a triangle that has a base of 16 and height of 14?
The area of a triangle equals half of the length of its base times its height.Area of a triangle with base of 16 units and height of 14 units is 112 square units.
The area of a rectangle that has 112 square inches?
122 square inches
If a rectangle is 8 ft by 14ft what is the area?
112 sq. ft.
What is the area of parallelogram who altitude is 14 inches and who base is 8 inches?
To find the area of a square or rectangle (a parallelogram is also a rectangle if two of the sides are a different length), you multiply length x width. Multiply 14 x 8 and you get 112.
What is the area of a triangle the base of 8 and one sixteen and the height of 3 and one seventh?
Area = 1/2 * 81/16 * 31/7 = 1/2 * 129/16 * 22/7 = 1419/112 = 1275/112
If a rectangle is 8 feet by 14 feet what is the area?
Area = Length * Width Area = 8 * 14 = 112 square feet =============
What is the area of a triangle with lenght of 16in and height of 14in?
If "length" means "length of side to which the height of 14 inches is perpendicular", area = (1/2)(14)(16) = 112 square inches. (These dimensionss of a triangle are more commonly called "base" and "altitude" respectively.)
What is the area of a triangle with a base of 14 cm and a height of 6 cm?
The area of a triangle is calculated using the formula A = 0.5 * base * height. Plugging in the given values, we get A = 0.5 * 14 cm * 6 cm = 42 square cm. Therefore, the area of the triangle is 42 square cm.
What is the area of a rectangle that has a length of 28 cm and a width of 4 cm?
Area = Length *Width = 28*4 = 112 sq cm
How many square feet in a rectangle 7x16?
There are 112 square feet in a rectangle that is 7 feet by 16 feet. This can be calculated by multiplying the length and width together (7 x 16 = 112).
One base of a trapezoid is three times as long as the other the height is the average of the two bases if the area of the trapezoid is 112yd find the length of the longer base?
Let the shorter base be ( b ) and the longer base be ( 3b ). The height is given as the average of the two bases, which is ( \frac{b + 3b}{2} = 2b ). The area of the trapezoid is given by the formula ( \text{Area} = \frac{1}{2} \times (b + 3b) \times \text{height} ), leading to ( 112 = \frac{1}{2} \times 4b \times 2b ). Simplifying gives ( 112 = 4b^2 ), so ( b^2 = 28 ) and ( b = \sqrt{28} = 2\sqrt{7} ). Therefore, the longer base is ( 3b = 6\sqrt{7} ) yards.
