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Q: What is the area of a regular polygon if its base is 5.2 mm and its height is 4.5 mm?

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The area of a four-sided polygon is base times height.

triangle

A triangle.

A regular pyramid has an equilateral triangle base, not just a regular polygon. It has an apex above the centre of the base.

The surface area of a pyramid is the area of all the faces of the pyramid, for a pyramid with apex in the centre and a regular polygon as its base, (the bottom of a pyramid is the base, it is regular if all sides are the same length) the surface area is: B + 1/2(P * H) where B is the area of the base, P is the perimeter (area around) the base and H is the height of the pyramid.

It's different for every polygon. For example, for a triangle, it's (1/2) x (base) x (height). For a rectangle, it's (the entire) (base) x (height).

Base: Depending on the shape of the base, use the formula for a square, a regular polygon, etc. Height: This must be measured (or calculated) perpendicular to the base.

regular pyramid

Regular Polygon...

vertex

Naturally its perimeter and area will increase accordingly

Yes

Yes.

Area = Base * Height so Base = Area/Height

Base times Height divided by three. The base is perpendicular to the height, which ends at the highest point of the pyramid. To find the area of the base, one simply uses 2-dimensional geometry. Triangle: Base of triangle times height of triangle over 2 Any regular polygon: Apothem (perpendicular distance from orthocenter to a side) times perimeter divided by 2.

V= Base Area * Height

Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height

A regular pyramid has a regular polygon base and a vertex over the center of the base. By:Cherrylvr :)

The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.

You can find the height of a parallelogram given the area and base measures by working backwards from the area formula. The area of a parallelogram is found with the formula: Area = Base * Height To solve this equation for Height, we divide both sides by the base. Area / Base = (Base * Height) / Base Simplify: Area / Base = Height

Area = B + ( (PH)/2 ) Where B is the base area, P is the base perimeter and H is the piramid height.

You didn't say it was a regular pentagon. For an arbitrary pentagon, you would calculate its area as you would for any polygon: divide it up into triangles, and add up the areas of the triangle. The area of a triangle is 1/2 times the base times the height, the height being the length of the perpendicular dropped to the base from the opposite vertex.

base*height

Area = 1/2*Base*Height so Base = 2*Area/Height

Surface Area= 1/2perimeter x slant height + B * * * * * Perimeter = perimeter of base. B = Area of base.