Since the legs are both 10, it is an isosceles trapezium. Using Pythagoras's theorem, the height of the trapezium is 8 and so its area is
1/2*(22 + 10)*8 = 128 square units.
Area = average of bases * height = (7 + 10)/2 * 10.6 = 8.5*10.6 = 90.1 sq units.
A trapezoid has two bases of different lengths. So there's a number missingfrom the question, and the area can't be calculated without it.
Area of a trapezoid= 0.5*(sum of parallel sides)*height
Area = 1/2 (sum of bases) times height Area = (8+12)/2 x 4 Area = 10 x 4 = 40
formula for area of a trapezoidA= 1/2 *(a+b) *hA- areaa and b represent basesh- haightA=1/2 * (15+10) * 5A= 62.5 inand that's the final answer :)))
42
Area = average of bases * height = (7 + 10)/2 * 10.6 = 8.5*10.6 = 90.1 sq units.
A trapezoid has two bases of different lengths. So there's a number missingfrom the question, and the area can't be calculated without it.
Area = 1/2*(100+75)*10 = 875 square feet
Trapezoid #1 . . . Height = 10, Bases = 10 and 20Trapezoid #2 . . . Height = 10, Bases = 14 and 16Area of each one is 150 square units.
Area of a trapezoid= 0.5*(sum of parallel sides)*height
Area = 1/2 (sum of bases) times height Area = (8+12)/2 x 4 Area = 10 x 4 = 40
Area of the trapezoid: 0.5*(8+11)*10 = 95 square measurements
((B+b)h)/2=area of a trapeziod B= larger base b=smaller base h=height ((10+8)5)/2= 45
formula for area of a trapezoidA= 1/2 *(a+b) *hA- areaa and b represent basesh- haightA=1/2 * (15+10) * 5A= 62.5 inand that's the final answer :)))
The average(mean) of the two bases. (8+12)/2=10
Area of a trapezoid = 0.5*(sum of parallel sides)*height