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A trapezoid has two bases of different lengths. So there's a number missing

from the question, and the area can't be calculated without it.

Q: What is the area of a trapezoid with 10 inches base and 8 inches height?

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The area of any trapezoid is 1/2 times (length of one base plus length of the other base) times (height). You ought to be able to handle it from there.

Area = 0.5*(5+7.5)*6 = 37.5 square inches

Area = 1/2*(15+9)*7 = 84 square inches

Assuming the height is 13 inches (not 13 feet or something else), Area = 0.5*(12+14)*13 = 169 sq inches.

For a parallelogram, take the base times the height. For a trapezoid, take the smaller base and times it by the height.

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The area of any trapezoid is 1/2 times (length of one base plus length of the other base) times (height). You ought to be able to handle it from there.

Area = 0.5*(17+11)*9 = 126 square inches.

Area = 0.5*(5+7.5)*6 = 37.5 square inches

Area = 1/2*(15+9)*7 = 84 square inches

Assuming the height is 13 inches (not 13 feet or something else), Area = 0.5*(12+14)*13 = 169 sq inches.

For a parallelogram, take the base times the height. For a trapezoid, take the smaller base and times it by the height.

The height of the trapezoid is also needed to find its area which is as follows:- Area of a trapezoid = 0.5*(sum of bases or parallel sides)*height

Height of trapezoid = 2*area/sum of parallel sides

Area of a trapezoid = 0.5*(sum of parallel bases)*height Need to know the measure of the other base

The perimeter of a trapezoid is the sum of its bases and legs. The area of a trapezoid is the height times (base 1 + base 2) divided by 2

The area of a trapezoid is: base 1 + base 2 times height divided by 2. :) I hope I helped you out a bit ^^

Yes, certainly. The trapezoid area is one half sum of bases times height and the parallelogram area is base times height If the base of the parallelogram is equal to 1/2 the sum of he trapezoid bases, they have the same area