area= 121.5
Area = 0.5*base*height 27 = 0.5*12*height = 6*height So height = 27/6 = 4.5 feet.
216 feet
The area of a triangle cannot be 270 cm because area is a 2-dimensional measure and so must be measured in square centimetres. Assuming it is 270 cm2, Area = 0.5*Base*Height 270 = 0.5*27*H so H = 20 cm.
17 cmImproved Answer:-Area = 1/2*6*9 = 27 square cm
You can cut the tapered ends off of the trapezoid, and calculate the individual areas of the three pieces. The center piece is a rectangle, Length = 27, Height = H. Area = 27H. Each end is a triangle, Base = 2, Height = H. Area = (1/2 base) times (height) = 1H (Left-end triangle) + (center rectangle) + (right-end triangle) = 1H + 27H + 1H = 29H. 29H = 348 cm2 H = 348/29 = 12 cm
1/2 base x height = area. So, 27 divided by 6 = 4.5
Area = 0.5*base*height 27 = 0.5*12*height = 6*height So height = 27/6 = 4.5 feet.
The area of a triangle is one half base times height. 1/2 Base Height = Area 1/2 Base 8 = 108 Base 8 = 216 Base = 27
216 feet
Area of triangle = (1/2) x (base) x (height) In our case it is (1/2) x 11 x 5 = 55/2 = 27 and 1/2 square units
A=.5bh_____27ft square=.5*12*h____27=6h_____4.5=h_____so the height is 4.5 feet
the formula is half base times height if the base is 6. divide it by 2, which would give you 3. 3 times 9 = 27
The area of a triangle cannot be 270 cm because area is a 2-dimensional measure and so must be measured in square centimetres. Assuming it is 270 cm2, Area = 0.5*Base*Height 270 = 0.5*27*H so H = 20 cm.
17 cmImproved Answer:-Area = 1/2*6*9 = 27 square cm
Area=(1/2)(Base)(Height) 27=(1/2)(12)(H) 54=(12)(H) H=4.5 check: 1/2(B)(H)=A 1/2(12)(4.5)=27 ? (6)(4.5)=27 ? 27=27
You can cut the tapered ends off of the trapezoid, and calculate the individual areas of the three pieces. The center piece is a rectangle, Length = 27, Height = H. Area = 27H. Each end is a triangle, Base = 2, Height = H. Area = (1/2 base) times (height) = 1H (Left-end triangle) + (center rectangle) + (right-end triangle) = 1H + 27H + 1H = 29H. 29H = 348 cm2 H = 348/29 = 12 cm
XXVII = 27 An equilateral triangle with a perimeter of 27 inches has three equal sides of 9 inches. Area of a triangle = base times its perpendicular height divided by 2. An equilateral triangle can be considered as being two right angled triangles joined together. So by halving the length of the base we can find its height by using Pythagoras' Theorem: hypotenuse2 - base2 = height2 92-4.52 = 60.75 square inches. Square root of 60.75 = 7.794228634 inches. Area = 9x7.794228634/2 = 35.07402885 square inches. Therefore area of an equilateral triangle with a perimeter of 27 inches is 35.074 square inches correct to 3 decimal places. Answered by David Gambell, Merseyside, England.