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area= 121.5

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Q: What is the area of a triangle if the base is 9 and the height is 27?
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What is the height of a triangle with 27 as area and 12 as base?

1/2 base x height = area. So, 27 divided by 6 = 4.5


What is the height of a triangle with the area of 27ft2 and base of 12 ft?

Area = 0.5*base*height 27 = 0.5*12*height = 6*height So height = 27/6 = 4.5 feet.


How long is the base of a triangle whose area is 108 and height is 8?

The area of a triangle is one half base times height. 1/2 Base Height = Area 1/2 Base 8 = 108 Base 8 = 216 Base = 27


What is the area of a triangle with a base of 27 feet and a height of 16 feet?

216 feet


What is the area of a triangle with a base of 11 and a height of 5?

Area of triangle = (1/2) x (base) x (height) In our case it is (1/2) x 11 x 5 = 55/2 = 27 and 1/2 square units


What is the height of a triangle that the area is 27 feet and the base is 12 feet?

A=.5bh_____27ft square=.5*12*h____27=6h_____4.5=h_____so the height is 4.5 feet


What is the area of a triangle with a height of 9 ft and a base of 6 ft?

the formula is half base times height if the base is 6. divide it by 2, which would give you 3. 3 times 9 = 27


What is the height of a triangle with a area of 270cm and a base 27cm?

The area of a triangle cannot be 270 cm because area is a 2-dimensional measure and so must be measured in square centimetres. Assuming it is 270 cm2, Area = 0.5*Base*Height 270 = 0.5*27*H so H = 20 cm.


What is the area of a triangle with a base of 6 cm and a height of 9 cm?

17 cmImproved Answer:-Area = 1/2*6*9 = 27 square cm


What is the height of a triangle that has an area of 27 squared feet and base that measures 12 ft?

Area=(1/2)(Base)(Height) 27=(1/2)(12)(H) 54=(12)(H) H=4.5 check: 1/2(B)(H)=A 1/2(12)(4.5)=27 ? (6)(4.5)=27 ? 27=27


How do you find the unknown height of a trapezoid if the bases are 27cm and 31 cm and the area is 348cm2?

You can cut the tapered ends off of the trapezoid, and calculate the individual areas of the three pieces. The center piece is a rectangle, Length = 27, Height = H. Area = 27H. Each end is a triangle, Base = 2, Height = H. Area = (1/2 base) times (height) = 1H (Left-end triangle) + (center rectangle) + (right-end triangle) = 1H + 27H + 1H = 29H. 29H = 348 cm2 H = 348/29 = 12 cm


Can you work out the area of an equilateral triangle with a perimeter of XXVII inches giving details of your work?

XXVII = 27 An equilateral triangle with a perimeter of 27 inches has three equal sides of 9 inches. Area of a triangle = base times its perpendicular height divided by 2. An equilateral triangle can be considered as being two right angled triangles joined together. So by halving the length of the base we can find its height by using Pythagoras' Theorem: hypotenuse2 - base2 = height2 92-4.52 = 60.75 square inches. Square root of 60.75 = 7.794228634 inches. Area = 9x7.794228634/2 = 35.07402885 square inches. Therefore area of an equilateral triangle with a perimeter of 27 inches is 35.074 square inches correct to 3 decimal places. Answered by David Gambell, Merseyside, England.