XXVII = 27 An equilateral triangle with a perimeter of 27 inches has three equal sides of 9 inches. Area of a triangle = base times its perpendicular height divided by 2. An equilateral triangle can be considered as being two right angled triangles joined together. So by halving the length of the base we can find its height by using Pythagoras' Theorem: hypotenuse2 - base2 = height2 92-4.52 = 60.75 square inches. Square root of 60.75 = 7.794228634 inches. Area = 9x7.794228634/2 = 35.07402885 square inches. Therefore area of an equilateral triangle with a perimeter of 27 inches is 35.074 square inches correct to 3 decimal places. Answered by David Gambell, Merseyside, England.
Yes providing that it is an equilateral triangle or a a right angle isosceles triangle other wise it's not possible
I am assuming that "traingle" is meant to be triangle and "permeter" is meant to be perimeter.The area of a triangle cannot be equal to its perimeter because the area is a measure in 2-dimensional space whereas a perimeter is a 1-dimensional measure. So their dimensions will always be different.Furthermore, the area of a triangle is not determined by its perimeter. The area of a triangle can be changed - without affecting its perimeter - simply by changing the angles.
Height in inches = XV=15 Area of a triangle = base length times perpendicular height divided by 2 An equilateral triangle has three equal sides with three equal interior angles of 60o An equilateral triangle can be considered as being two right angled triangles joined together. So we can make use of trigonometry to find the base length: opposite/tangent = adjacent length of the right angled triangle 15/tangent 60o = 8.660254038 inches Base length of the equilateral triangle = 8.660254038*2 = 17.32050808 inches Area = 17.32050808*15/2 = 129.9038106 square inches Therefore the area of the equilateral triangle is 130 square inches which is correct to three significant figures. Answered by David Gambell, Merseyside, England.
So cut the triangle in half, giving it 90 degrees angle in one of the angles.Then Use pathogorean theorem.So 9 squared + b Squared = 18 squared81+b squared = 334 squaredAnswer: Square root of 233
The smallest perimeter possible is if the shape is a circle of radius 1.32 metres (approx). This gives a perimeter of 8.313 metres. If the shape is a rectangle, it will have minimum perimeter when it is a square with sides of 2.34 metres, giving a perimeter of 9.381 metres. But it cound be a rectangle with width 0.001 metres and length of 5500 metres giving a perimeter of just over 11 KILOmetres. The perimeter can be increased without limit.
In an equilateral triangle, all 3 sides are the same length, so your equation would look something like this: P=the perimeter of the triangle (x+3)=length of each side P=3(x+3) If you wanted to simplify further, you would distribute the 3 to both the x and the 3 inside of the parentheses, giving you P=3x+9.
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
Yes providing that it is an equilateral triangle or a a right angle isosceles triangle other wise it's not possible
I am assuming that "traingle" is meant to be triangle and "permeter" is meant to be perimeter.The area of a triangle cannot be equal to its perimeter because the area is a measure in 2-dimensional space whereas a perimeter is a 1-dimensional measure. So their dimensions will always be different.Furthermore, the area of a triangle is not determined by its perimeter. The area of a triangle can be changed - without affecting its perimeter - simply by changing the angles.
Height in inches = XV=15 Area of a triangle = base length times perpendicular height divided by 2 An equilateral triangle has three equal sides with three equal interior angles of 60o An equilateral triangle can be considered as being two right angled triangles joined together. So we can make use of trigonometry to find the base length: opposite/tangent = adjacent length of the right angled triangle 15/tangent 60o = 8.660254038 inches Base length of the equilateral triangle = 8.660254038*2 = 17.32050808 inches Area = 17.32050808*15/2 = 129.9038106 square inches Therefore the area of the equilateral triangle is 130 square inches which is correct to three significant figures. Answered by David Gambell, Merseyside, England.
So cut the triangle in half, giving it 90 degrees angle in one of the angles.Then Use pathogorean theorem.So 9 squared + b Squared = 18 squared81+b squared = 334 squaredAnswer: Square root of 233
The smallest perimeter possible is if the shape is a circle of radius 1.32 metres (approx). This gives a perimeter of 8.313 metres. If the shape is a rectangle, it will have minimum perimeter when it is a square with sides of 2.34 metres, giving a perimeter of 9.381 metres. But it cound be a rectangle with width 0.001 metres and length of 5500 metres giving a perimeter of just over 11 KILOmetres. The perimeter can be increased without limit.
The perimiter of a shape is the distance around its edge, in this case 10 +17 + 21 giving a total of 48 inches, or four feet if you want to convert it.
The lengths of the sides of the triangle are: 2*sq rt of 10, 5*sq rt of 2 and sq rt of 10 The 3 sides added together equals the perimeter which works out as 3* sq rt of 10 plus 5*sq rt of 2 in surd form
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giving the important things details
Area = 1/2*base*height =24 cm2 Multiply both sides by 2: base*height = 48 Factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48 The only above numbers that will satisfy the criteria for the area and perimeter of the triangle are 6 and 8 because: Area = 1/2*6*8 = 24 cm2 Perimeter = 6+8+10 = 24 cm Therefore the length of the hypotenuse is 10 cm because it's the longest side. Check using Pythagoras' Theorem: 62+82 = 100 and the square root of this is 10