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Area = 0.5*6*8 = 24 square inches

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Q: What is the area of a triangle that has a base of 6inches and an altitude of 8 inches?
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What is the area of the triangle with sides 6inches 5inches and 10inches?

A triangle with side a: 6, side b: 5, and side c: 10 inches has an area of 11.4 square inches.


The altitude of a triangle is 5 inches less than its base. the area of the triangle is 42 square inches . find its base and altitude?

The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches


What is the area of a triangle with a base of 10in and an altitude of 14in?

70 square inches


A triangle has an area of 144 sq inches and its base is 2 ft long What is the altitude of the triangle?

First convert the base to the same kind of units you have defined the area in (but linear); 24 inches. The area of a triangle is half of the base times the height .12 (half the base) times what is 144?12, the height (altitude) of the triangle is 12 inches (one foot).


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What is the area of a triangle having a base of 16 inches and an altitude of 4 inches?

32 inches squared. 16 times 4 is 64, and divide by two since it is a triangle. You get 32 and it has to be inches squared because it is area.


What is the area of an equilateral triangle with a side of 20 inches?

Area = 1/2*altitude*base Area = 1/2*17.32050808*20 Area = 173.2050808 square inches The altitude or height was worked out by using Pythagoras' theorem.


The legs of a right triangle are 8 and 28 inches long what is the area?

The formula for the area (A) of any triangle is A = 1/2base x altitude (or height). The area of a right angled triangle with base = 8 and altitude = 28 is therefore :- A = 1/2 x 8 x 28 = 112 sq inches


A rectangle and triangle have equal areas. The rectangle is 12 inches long and 8 inches wide. If the base of the triangle is 32 inches what is the length in inches of the altitude drawn to the base?

The altitude will be 6 inches in length. The area of the rectangle is length (l) times width (w) or l x w = 12 x 8 = 96 The area of a triangle is 1/2 the base (b) times the height (h), or altitude, and, because the area of the triangle is equal to the area of the rectangle, both will have an area of 96. For the triangle, 1/2 b x h = 1/2 x 32 x h = 96, and 16 x h = 96, and h = 6


A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?

The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.


How do you calculate the altitude of a triangle?

Let the given area is 10cm. Base of the triangle is 4 cm. altitude of triangle=? Area= 1/2 x Base x altitude 10= 1/2 x 4x altitude 10=2 x altitude 10/2= altitude 5= altitude Hence, altitude of the triangle is 5 cm.


What would the area of a triangle with a base of 20 in and a height of 5 in?

Area = 0.5*Base*Altitude = 0.5*20*5 = 50 square inches.