Let s = semiperimeter (ie half the perimeter)
So s = (a+b+c)/2 = (5 + 8 + 11)/2 = 24/2 = 12
Then area = sqrt[s*(s-a)*(s-b)*(s-c)]
= sqrt[12*7*4*1] = sqrt[336] = 18.33 square units.
Area of a trapezoid = 0.5*(sum of parallel sides)*height
6 units of measurement Check: 1/2*6*10 = 30 square units
approximately 12.7
It is not possible to answer the question without information about which sides are parallel.
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
A triangle with side a: 5, side b: 8, and side c: 11 units has an area of 18.33 square units.
When you multiple the area of the small triangle by four it equals the area of the large triangle.
when you multiply the area of the small triangle by four it equals the area of the large triangle.
A = half(a+b)h where h equals height and a and b are the parallel sides.
The area of a rectangle equals its length times its width (A = l*w), so if you have the area divided by the one of the sides equals the other side (l = A/w; w = A/l )
Taking the four sides as each having 6 inch length, and the sum of the widths and heights of the sides being 14 inches, the area of the sides is 84 square inches (6 x 14), and the area of the ends is 24 square inches (2 x 3 x 4), for a total surface area of 108 square inches.
Area = square of ANY side. Since all the sides of a square are the same...