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35/2 cm² 0r 17.5 cm² area = 0.5 x base x height

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Q: What is the area of isosceles triangle that has a base of 5cm and a height of 7cm?

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Area of any triangle is: 0.5*base*perpendicular height

Area = 1/2*base*height = 0.825 sq cm. The fact that the triangle is isosceles is irrelevant: it makes no difference to its area.

area of a triangle is half the base times the height .5*22*28=308

An isosceles triangle has 2 equal base angles and its height is perpendicular from its apex to the centre of its base

For all triangles: area = 1/2 * base * height

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Area of any triangle is: 0.5*base*perpendicular height

Area = 1/2*base*height = 0.825 sq cm. The fact that the triangle is isosceles is irrelevant: it makes no difference to its area.

area of a triangle is half the base times the height .5*22*28=308

An isosceles triangle has 2 equal base angles and its height is perpendicular from its apex to the centre of its base

For all triangles: area = 1/2 * base * height

Area of isosceles triangle: 0.5*5*7 = 17.5 square cm

17.5cm squared

It depends on the size of the triangle.It is half the base times height.

The area of a triangle = 1/2*base*height = 1/2*5*7 = 17.5 cm2.The fact that it is an isosceles triangle is irrelevant.

For all triangles: area = 1/2 * base * height

The are of any triangle is calculated by the formula: Area = 1/2 x Base x Height

assuming its an isosceles triangle, then its 16 cm high