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What is the circumradius of an isosceles triangle?
To find the circumradius of an isosceles triangle, the formula is:1/8[(a^2/h)+4h]in which h is the height of the triangle and a is the base of the triangle.
Find the area of an isosceles triangle?
For all triangles: area = 1/2 * base * height
How do you find the base of an isosceles triangle if you know the angles and the height?
well it seems to me that i don't have a CLUE what your talking about !
What is the formula to find the area of an isosceles triangle?
For all triangles: area = 1/2 * base * height
How do you find the base of an isosceles triangle if the legs are 5 and the area 12?
Area of a triangle = 1/2*base*height 12 = 1/2*base*height 24 = base*height. Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. By trial and improvement lets take the base of the triangle as 6 and its height as 4 An isosceles triangle contains two right angle triangles which in this case they have a base of 3, a height of 4 and a hypotenuse of 5 Using Pythagoras' theorem: 32+42 = 52 From the above information we can deduce that the base of the isosceles triangle is 6 units in length.
