To find the circumradius of an isosceles triangle, the formula is:1/8[(a^2/h)+4h]in which h is the height of the triangle and a is the base of the triangle.
For all triangles: area = 1/2 * base * height
well it seems to me that i don't have a CLUE what your talking about !
For all triangles: area = 1/2 * base * height
Area of a triangle = 1/2*base*height 12 = 1/2*base*height 24 = base*height. Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. By trial and improvement lets take the base of the triangle as 6 and its height as 4 An isosceles triangle contains two right angle triangles which in this case they have a base of 3, a height of 4 and a hypotenuse of 5 Using Pythagoras' theorem: 32+42 = 52 From the above information we can deduce that the base of the isosceles triangle is 6 units in length.
To find the circumradius of an isosceles triangle, the formula is:1/8[(a^2/h)+4h]in which h is the height of the triangle and a is the base of the triangle.
i can
For all triangles: area = 1/2 * base * height
By using Pythagoras' theorem.
well it seems to me that i don't have a CLUE what your talking about !
For all triangles: area = 1/2 * base * height
Only a right triangle has a hypotenuse. An isosceles triangle can be a right triangle but it doesn't have to be. If it's not, then it doesn't have a hypotenuse.
Area of a triangle = 1/2*base*height 12 = 1/2*base*height 24 = base*height. Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. By trial and improvement lets take the base of the triangle as 6 and its height as 4 An isosceles triangle contains two right angle triangles which in this case they have a base of 3, a height of 4 and a hypotenuse of 5 Using Pythagoras' theorem: 32+42 = 52 From the above information we can deduce that the base of the isosceles triangle is 6 units in length.
To find the area of any triangle... divide the length of the base by 2... then multiply the result by the height.
An isosceles triangle can be split up into two right angle triangles so use trigonometry to find the base and then double your answer to find the base of the isosceles triangle which works out as 57.12592026 meters. Base = 20/tan(35) = 28.56296013 Base of isosceles = 28.56296013*2 = 57.12592026 Area = 1/2*base*height Area = 1/2*57.12592026*20 = 571.2592026 square meters
Ok to find the area of an isosceles triangle: Find the height first, to do this use this formula: Height = Square root ( one side square - half the base square) Now that you have the height you can calculate the area by the use of this formula: Area = (1/2)(base)(height) This will give you the surface area of an isosceles triangle. Lets do an example: You have a triangle that has two sides that measure 24 meters and a base of 20 meters. Using the formula above for height you will get a height of 21.8 meters Now use the formula above to find the area and it will give you an area of 218 meters square
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.