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What is the area of the quadrilateral ABCD in which AB is 4.3 mm BC is 3.4 mm CD is 3.8 mm angle ABC is 95 degrees and angle BCD is 115 degrees?
Wiki User
∙ 6y ago
Using the cosine rule diagonal BD is 6.08 mm which splits angle 95 degrees into angles of 34.5 degrees and 60.5 degrees and so the area of the quadrilateral is:-
0.5*6.08*3.4*sin(34.5) plus 0.5*6.08*4.3*sin(60.5) = 17.232 square mm
Wiki User
∙ 6y ago
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What is the area of a quadrilateral in which angle 109 degrees is between sides 0.38cm and 0.69cm when adjacent angle 123 degrees is between sides 0.38cm and 0.42cm?
Here's how I solve it using the Sine and Cosine rules, and area of a triangle based on sine of angle between two given lengths:Let the quadrilateral be ABCD with ADC = 109°, DCB = 128°, AD = 0.69cm, DC = 0.38cm, CB = 0.42cmDraw in diagonal AC. Area quadrilateral = area ACD + area ABC.Length AC can be found from the cosine rule on triangle ADC:AC = √(0.69² + 0.38² - 2 × 0.69 × 0.38 × cos 109°) cm ≈ 0.89 cmAngle ACD can be found using the sine rule:ACD = arc sin(0.69/0.89 × sin109°) ≈ 47.18°→ BCD = 128 - ACD ≈ 80.82°→ area quadrilateral ≈ ½ × 0.69 cm × 0.38 cm × sin 109° + ½ × 0.42 cm × 0.89 cm × sin 80.82°≈ 0.308 cm²Another Answer: Using triangulation and trigonometry the area of the 4 sided quadrilateral works out as 0.305 square cm rounded to three decimal places.
What is the area of the quadrilateral ABCD when AB is 0.38cm BC is 0.69cm and AD is 0.42cm with angles ABC 109 degrees and BAD 123 degrees?
Form two triangles from diagonal A to C and by finding the areas of each triangle they will add up to 0.305 square cm rounded to three decimal places.
What is the area of an obtuse angle?
You do not find are of an angle however an obtuse angle mesures greater than 90 degrees.
How can you calculate the area of an angle of 75x75x12?
With great difficulty because angles are degrees of measurement and not area.
How do you calculate 45 degree area?
The 45 degrees is an angle. To calculate an area the length and width are needed.
What is the area of the quadrilateral abcd in which ab is 0.38 cm bc is 0.69 cm ad is 0.42 cm angle abc is 109 degrees and angle bad is 123 degrees?
Using trigonometry the area of the given quadrilateral works out as 0.305 square cm
What is the area of a quadrilateral when angle 123 degrees is between sides 0.38cm and 0.42cm with angle 109 degrees between sides 0.69cm and 0.38cm?
By sketching a diagram and then using trigonometry the area of the 4 sided quadrilateral works out as 0.305 square cm to three decimal places
What is the area of a quadrilateral in which angle 109 degrees is between sides 0.38cm and 0.69cm when adjacent angle 123 degrees is between sides 0.38cm and 0.42cm?
Here's how I solve it using the Sine and Cosine rules, and area of a triangle based on sine of angle between two given lengths:Let the quadrilateral be ABCD with ADC = 109°, DCB = 128°, AD = 0.69cm, DC = 0.38cm, CB = 0.42cmDraw in diagonal AC. Area quadrilateral = area ACD + area ABC.Length AC can be found from the cosine rule on triangle ADC:AC = √(0.69² + 0.38² - 2 × 0.69 × 0.38 × cos 109°) cm ≈ 0.89 cmAngle ACD can be found using the sine rule:ACD = arc sin(0.69/0.89 × sin109°) ≈ 47.18°→ BCD = 128 - ACD ≈ 80.82°→ area quadrilateral ≈ ½ × 0.69 cm × 0.38 cm × sin 109° + ½ × 0.42 cm × 0.89 cm × sin 80.82°≈ 0.308 cm²Another Answer: Using triangulation and trigonometry the area of the 4 sided quadrilateral works out as 0.305 square cm rounded to three decimal places.
What is the area of a quadrilateral having sides in cm of 3 by 4 by 7.4 by 4.4 when the angle between sides 3 and 4 is 90 degrees?
Using trigonometry the area of the quadrilateral works out as 16.688 square cm rounded to three decimal places
What is the area of the quadrilateral ABCD when AB is 0.38cm BC is 0.69cm and AD is 0.42cm with angles ABC 109 degrees and BAD 123 degrees?
Form two triangles from diagonal A to C and by finding the areas of each triangle they will add up to 0.305 square cm rounded to three decimal places.
What is the area of a quadrilateral that has sides of 1.5cm 2cm 3.7cm and 2.2cm respectively in the given order?
The quadrilateral has a diagonal of 2.5 cm and using the cosine formula the 'included' angle between sides 1.5cm and 2cm is 90 degrees also the 'included' angle between sides 3.7cm and 2.2cm is 41.036 degrees rounded to 3 decimal places. Area of quadrilateral: 0.5*1.5*2*sin(90)+0.5*3.7*2.2*sin(41.036) = 4.172 square cm rounded to 3 decimal places
What is the measure of a regular quadrilateral?
A regular quadrilateral is a square. As to the measure, the answer depends on the measure of WHAT? An angle, a side, the diagonal, area, perimeter, etc.
What is the area of an obtuse angle?
You do not find are of an angle however an obtuse angle mesures greater than 90 degrees.
What is a area of an interior angle?
Anything under 180 degrees
What is the area of quadrilateral with 4 unequal sides?
You need to know the lengths of the sides and at least one angle or the length of a diagonal.
How can you calculate the area of an angle of 75x75x12?
With great difficulty because angles are degrees of measurement and not area.
What is the area of a circle if the area of its sector is 49?
The area of the circle is(17,640)/(the number of degrees in the central angle of the sector)
