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When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.

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Q: What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -5 -17 giving the reason for your answer?
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