Assuming these number are the coordinate pairs of a triangle then use Pythagoras to determine the lengths of the sides. Then use Hero's formula to calculate the area from the sides. Beyond that I can't be bothered to do it.
5 + 6 = 11 6 + 5 = 11 11 - 6 = 5 11 - 5 = 6
-5 - 6 = -11
Multiplication is simply repetitive addition. For instance, the expanded form of 2 * 3 is: 2 + 2 + 2, or 3 + 3. The expanded form of 5 * 6 is: 5 + 5 + 5 + 5 + 5 + 5, or 6 + 6 + 6 + 6 + 6. From the information above, it is evident that 11 * 5 = 11 + 11 + 11 + 11 + 11, and 11 * 6 = (11 * 5) + 11 So, substitute 55 for 11 * 5: 11 * 6 = 55 + 11 11 * 6 = 66
6 and 5 11 in decimals = 6.45456 5/11= 6 + (5 ÷ 11)= 6 + 0.4545= 6.4545
The output of the expression 11 5 will be 6. This is because 11 - 5 = 6.
6
5/6 divided by 5/11 = 5/6 (11/5) = 11/6
1 5/6 = (1×6+5)/6 = 11/6 → 1/(1 5/6) = 1/(11/6) = 6/11
5 + 6/11 = 55/11 + 6/11 = 61/11
foest and hills area 6 11 and 5
1
-11