26
47 + 5 / 2
47 - 5 = 42 (42 is the difference).
9
The arithmetic mean of 2, 5, 5, 1 and 9 is 4.4
It is: 8+8+8+5+6 = 35 and 35*5 = 7 which is the mean
To find the first arithmetic mean between -15 and 9 with three means inserted, we first calculate the total number of terms, which is 5: -15, A1, A2, A3, and 9. The common difference (d) can be calculated as the difference between the last term and the first term divided by the number of intervals (4). Thus, ( d = \frac{9 - (-15)}{4} = \frac{24}{4} = 6 ). The first arithmetic mean (A1) is then -15 + 6 = -9.
65.
47 - 5 = 42 (42 is the difference).
The arithmetic mean is 6.5
9
The arithmetic mean of 2, 5, 5, 1 and 9 is 4.4
The average or mean of 3, 5, 7, 9, and 11 is 7.
It is: 8+8+8+5+6 = 35 and 35*5 = 7 which is the mean
The mean of those data points is 9.
5
The answer depends on the arithmetic operator between 5 and 6.25 and without it, there is no way to answer the question.
The arithmetic mean of a set of numbers is found by dividing the sum of all the numbers by how many numbers there are. In this case the arithmetic mean is: (8 + 7 + 7 + 5 + 3 + 2 + 2) / 7 ---> because there are 7 pieces of data. = 34 / 7 = 4.857 ( to 3 d.p.)
Assuming the space is between the 5 and the 37, you could put 21 in there and all the numbers would be 16 apart from each other.