Assuming the space is between the 5 and the 37, you could put 21 in there and all the numbers would be 16 apart from each other.
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In it is an arithmetic sequence then the missing cannot be at the end. It is 21, between the 5 and 37,
The answer depends on where, within the sequence, the missing number should have been.
yes it is
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
It all depends on the sequence you are talking about. For example, the next number in the sequence 0,1,1,2,3,5,8,13,_ would be 21. This would be the Fibonacci sequence as the rule is add the 2 previous terms to get the next term. Another example would be this: 11,121,1331,14641,______.The missing number is 161051, following the pattern of powers of 11, 11^1, 11^2, 11^3 and so on. If you understand what I am trying to say, it all depends on the sequence you are trying to find the number in.
14