16 + 18 + 14 +12
______________ = 30
2
16
11- undecagon 12- dodecagon 13- 13-gon 14- 14-gon 15- 15-gon 16- 16-gon 17- 17-gon 18- 18-gon 19- 19-gon 20- 20-gon
On average 16-18
no.
It is quite acceptable to call them 11-agon 12-agon 13-agon ..... ect but what is more important is knowing how to work out their properties.
(12+14+16+18)/4 = 15
16
There are probably tens of such sets. Some are: 5, 6, 7, 7, 8, 11, 13, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 16, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 16, 18
Assuming is meant 10 12 14 16 18= total 70there are five numbersso 70 / 5 = 14
4, 6, 8, 9, 10, 12, 14, 15, 16, 18 The average is 11.2
6 + 10 + 14 + 18 = 48/4 = 12 The average of the four numbers is 12.
6 + 10 + 14 + 18 = 48/4 = 12 The average of the four numbers is 12.
The mode is 16.
12, 14, 15, 16, 18 and 20
Based on the sample you have provided, I see that 4 numbers, counting by 2 from 12 to 18, form a repeating sequence. I would expect that the next 4 numbers in this series would again be 12, 14 16, and 18.
(15*12+16*15+18*14)/4913.7142857 is the true average age
The composite numbers between 11 and 19 are 12, 14, 15, 16 and 18