16
11- undecagon 12- dodecagon 13- 13-gon 14- 14-gon 15- 15-gon 16- 16-gon 17- 17-gon 18- 18-gon 19- 19-gon 20- 20-gon
On average 16-18
no.
It is quite acceptable to call them 11-agon 12-agon 13-agon ..... ect but what is more important is knowing how to work out their properties.
16
To find the average of a set of numbers, you add all the numbers together and then divide by the total count of numbers. In this case, the sum of 16, 18, 14, and 12 is 60. Since there are four numbers in the set, you divide 60 by 4 to get an average of 15.
There are probably tens of such sets. Some are: 5, 6, 7, 7, 8, 11, 13, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 16, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 16, 18
Assuming is meant 10 12 14 16 18= total 70there are five numbersso 70 / 5 = 14
4, 6, 8, 9, 10, 12, 14, 15, 16, 18 The average is 11.2
6 + 10 + 14 + 18 = 48/4 = 12 The average of the four numbers is 12.
6 + 10 + 14 + 18 = 48/4 = 12 The average of the four numbers is 12.
The mode is 16.
Based on the sample you have provided, I see that 4 numbers, counting by 2 from 12 to 18, form a repeating sequence. I would expect that the next 4 numbers in this series would again be 12, 14 16, and 18.
(15*12+16*15+18*14)/4913.7142857 is the true average age
The composite numbers between 11 and 19 are 12, 14, 15, 16 and 18
-2, -4, -6, -8, -10, -12, -14, -16, -18, -20