Q: What is the average of 26 32 and 41?

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44.3

average = Sum of all terms / No. of terms = ( 31 + 29 + 26 + 27 + 32 ) / 5 = 145 / 5 = 29 therefore the average is 29!

41 x 32 = 1312 -------------------------------------- The last digit of 41 × 32 is 1 × 2 = 2, but the last digit of 235 is 5. 2 does not equal 5, thus 41 × 32 does not equal 235.

1 with 9 remaining 41 - 9 = 32 = 32 x 1 or 1.28125

3200/41 = 78.05

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44.3

66

average = Sum of all terms / No. of terms = ( 31 + 29 + 26 + 27 + 32 ) / 5 = 145 / 5 = 29 therefore the average is 29!

-32, -21, 30, 32, 41

32/41 is the simplest form.

n + 26 = 41 n = 41 - 26 n = 15 Thanks

(25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41) / 17 => 561/17 => 33 The Answer

41 x 32 = 1312 -------------------------------------- The last digit of 41 × 32 is 1 × 2 = 2, but the last digit of 235 is 5. 2 does not equal 5, thus 41 × 32 does not equal 235.

the answeer is 26

-41

1 with 9 remaining 41 - 9 = 32 = 32 x 1 or 1.28125

what is 33 p 41 p 26