Q: What is the average of the integers from 25 to41?

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it is 33; you can add all up and divide by 17, or simply add first and last and divide by 2

You are asking for the arithmetic mean for 25 consecutive integers starting at 13. (13+14+...+36+37) / 25 = 25 But there is a trick to this question. Since (13+37)/2 = (14+36)/2 = (15+35)/2 = ... = (24+26)/2 = 25/1 = 25, you only needed to calculate (13+37)/2 =25. The same is true for any sum of consecutive integers. For more information, look up "arithmetic series".

The integers are 24, 25 and 26.

A triplet of integers.

7 23 + 25 + 27 = 75. The largest of these 3 integers is 27.

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The average of the integers 25 and 41 is 33. Average is found by adding up the integers and dividing that number by the number of integers that were added together. So, 25+41=66, then 66/2=33.

It is 33.

66

It is 33.

It is 33.

33

66

it is 33; you can add all up and divide by 17, or simply add first and last and divide by 2

186

25 was exactly 25 in 1910. The value of integers has not changed since they were first conceived.25 was exactly 25 in 1910. The value of integers has not changed since they were first conceived.25 was exactly 25 in 1910. The value of integers has not changed since they were first conceived.25 was exactly 25 in 1910. The value of integers has not changed since they were first conceived.

To find the average of integers, add them all together then divide the total by the number of integers.

You are asking for the arithmetic mean for 25 consecutive integers starting at 13. (13+14+...+36+37) / 25 = 25 But there is a trick to this question. Since (13+37)/2 = (14+36)/2 = (15+35)/2 = ... = (24+26)/2 = 25/1 = 25, you only needed to calculate (13+37)/2 =25. The same is true for any sum of consecutive integers. For more information, look up "arithmetic series".