The average is 16.
Average(5, 10, 15) = (5 + 10 + 15)/3 = 30/3 = 10
To find the average of a set of numbers, you add up all the numbers and then divide by the total count of numbers. In this case, the sum of 15, 30, and 45 is 90. Since there are three numbers in the set, you divide 90 by 3 to get an average of 30.
2/3 + 3/5 =10/15 + 9/15= 19/15(19/15) / 2 = 19/3019/30
30 is divisible by 3, 5 & 15. Therefore, the L.C.M. of 3, 5, 30 & 15 is 30.
The LCM of 2, 3 and 15 is 30.
1. n + 3*5 = 30 2. n + 15 = 30 3. n + 15 = 30 - 15 -15 n = 15
The common factors of 15 and 30 are 1, 3, 5, and 15. Factors of 15 are 1, 3, 5, and 15. Factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30.
The factors of 15 are 1, 3, 5, and 15. The factors of 30 are 1, 2, 3, 5, 6. 10, 15, and 30. The common factors of 15 and 30 are 1, 3, 5, and 15.
Factors of 15 are 1, 3, 5, and 15. Factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30. Common factors of 15 and 30 are 1, 3, 5, and 15.
The answer of what's the GCF of 3, 15, and 30 = 3
3. 15/3 = 5. 27 / 3 = 9. 30/3=10
You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...