Q: What is the average of 3 plus 1 plus 1?

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3y+1

3+1+3+3+3+4+3+4+1+1+1+1+1+1+5+6 =41 Every operation is addition so all the adding can happen in one step.

It is 77

1

Average = (sum of the items) / (number of items)Sum of the items = (3x + 1) + (x - 3) = 4x - 2Number of items = 2Average = (2x - 1)

It is 123.99

The average of 0.3 and 3 and 30 is 11.1

it equals 62

(2x + 5) + (5x - 6) + (-4x + 2) = 3x + 1 There are three items so average = (3x + 1)/3 = x + 1/3

1/2 (3x + 1 + x - 3) = 1/2 (4x - 2) = 2x - 1

76

23

3 3/4

1 plus 3 is 4. of course

No, 1 plus 7 is not 3.

Yes: 1 + 1 + 1 = 3 which is 3×1 which is a multiple of 3, thus it is divisible by 3.

3 plus 1 plus 4 equals 8

-4

1 + 2 + 3 = 6

9+7+5+3+1 16+5+3+1 21+3+1 24+1 25

25

The same way you do it in any language: divide the sum by three.int x, y, z, average;x = 1;y = 3;z = 5;average = (x+y+z)/3;

1 + 2 + 3 + 4.99 = 10.99

1 + 2 + 3 + 4.1 = 10.1

43