You cannot add 3x and 1. You can add 3x and x and get 4x though.
2x2+7/x1
2x+x+5+3x-6=6x-1
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
12x2 + 7x + 1 = 12x2 + 3x + 4x + 1 = 3x*(4x + 1) + 1*(4x + 1) = (4x + 1)*(3x + 1)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
(X + 1)3 = X3 + 3X2 + 3X + 1
x3+3x2+3x+2 divided by x+2 equals x2+x+1
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
Assuming simplify = factor...x3 - 3x + 2 = (x-1)(x2+x-2)
(a) y = -3x + 1
No. Although it is increasing most of the time, it is decreasing between x=-1 and x=1.
∫ (x2+3) = ∫x2 + ∫3(1/3)X3 + 3X + C
lim (x3 + x2 + 3x + 3) / (x4 + x3 + 2x + 2)x > -1From the cave of the ancient stone tablets, we cleared away several feet of cobwebs and unearthed"l'Hospital's" rule: If substitution of the limit results in ( 0/0 ), then the limit is equal to the(limit of the derivative of the numerator) divided by (limit of the derivative of the denominator).(3x2 + 2x + 3) / (4x3 + 3x2 + 2) evaluated at (x = -1) is:(3 - 2 + 3) / (-4 + 3 + 2) = 4 / 1 = 1
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
1-3x1=3x 1/3=x
-x(x2 - 2)(x2 + 3)