The average is 80.
It is: (69/91)*100 = 75.82% to 2 decimal places
The number that's exactly half-way between 47 and 91, and the same distancefrom both of them, is their average. It's 69.
Ans- its 69
It is (47+91)/2 = 69
132, 69, 91
69
The average is 89.
The average is (64 + 69 +73)/3 = 206/3 = 68.66... recurring.The average is (64 + 69 +73)/3 = 206/3 = 68.66... recurring.The average is (64 + 69 +73)/3 = 206/3 = 68.66... recurring.The average is (64 + 69 +73)/3 = 206/3 = 68.66... recurring.
The average of the first 91 natural numbers can be calculated using the formula for the average of the first ( n ) natural numbers, which is given by ( \text{Average} = \frac{n(n + 1)}{2n} ). For ( n = 91 ), the sum of the first 91 natural numbers is ( \frac{91 \times 92}{2} = 4186 ). Dividing this sum by 91 gives an average of ( \frac{4186}{91} = 46 ). Therefore, the average of the first 91 natural numbers is 46.
(69+96)/2 = 82.5
The first integer must equal 77 - 69 = 8 , since doubling it increases the sum by this amount. Similarly, the second integer must = 91 - 69 = 22. Then the third integer is 69 - 22 - 8 = 39.
101.5 is the average.