If the acceleration was constant (15 + 25) /2 = 20
(time does not figure into the averaging at all!)
The average velocity is calculated by finding the distance traveled and dividing by the time it took to go that far. In high school, many people learn rate x time= distance. The rate is the average velocity.In this case we have 3.2/7.256=.441013 meters per second. Note the units are meters and seconds so the velocity we have it meters per second. We can convert this to any other units once we have this. Much as mile or meters per hour.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
900 m/s velocity=meters/sec v=4500/5=900
vt = velocity at time tv0 = initial velocitya = accelerationt = timevt = v0 + a * tvt = 1000 + 4 * 100vt = 1400 m/s
Average acceleration = (change in speed) / (time for the change) = (88 - 44) / (11) = 4 meters per second2
.5 meters per second.
Half a second every metre.
26
16.66 meters per second
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
The average velocity is calculated by finding the distance traveled and dividing by the time it took to go that far. In high school, many people learn rate x time= distance. The rate is the average velocity.In this case we have 3.2/7.256=.441013 meters per second. Note the units are meters and seconds so the velocity we have it meters per second. We can convert this to any other units once we have this. Much as mile or meters per hour.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
3.00 m/s
7500 meters per 10 seconds = 750 meters per second = 2,700 km per hour. That's a fast dog.
900 m/s velocity=meters/sec v=4500/5=900
You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?
vt = velocity at time tv0 = initial velocitya = accelerationt = timevt = v0 + a * tvt = 1000 + 4 * 100vt = 1400 m/s